Re: [exim] openldap + exim, how to make mailing group ?

トップ ページ
このメッセージを削除
このメッセージに返信
著者: George Sitov
日付:  
To: exim-users, George Sitov
題目: Re: [exim] openldap + exim, how to make mailing group ?
2009/11/17 Phil Pennock <exim-users@???>

> On 2009-11-16 at 22:30 +0300, George Sitov wrote:
> > 2009/11/16 Phil Pennock <exim-users@???>
> > > Change ?memberUid? to ?memberUid,mail?
> > >
> > > You can use ${extract{mail}{the_lookup}} to get the mail part from the
> > > results.
> > >
> > > -Phil
> > >
> >
> > It seems like:
> >
> > data = ${lookup ldapm{LDAP_AUTH \
> > ${extract{mail}{ldap:///ou=People,dc=xxx,dc=
> > org?memberUid?sub?(cn=${quote_ldap:$local_part})}}}
> >
> > ?
>
> No. See the bit between the first question-mark ("?") and the second
> question-mark? That's where you specify which attributes you want from
> LDAP.
>
> You are currently asking for just memberUid, so you're getting just
> that. You need to *ask* for the data you want. This is why I wrote:
>
> > Change ?memberUid? to ?memberUid,mail?
>
>
> After you ask LDAP for different data, if you're asking for more than
> one attribute per user, you'll need to figure out how to get just the
> data you want. The ${extract{}{}} then goes *around* the entire LDAP
> lookup.
>
> I recommend only asking for one attribute per user when using ldapm,
> it's *much* easier. So you'd use ?mail? *instead-of* ?memberUid?.
>
> So:
> data = ${lookup ldapm{LDAP_AUTH
> ldap:///ou=People,dc=xxx,dc=org?mail?sub?(cn=${quote_ldap:$local_part})}}
>



How i can get "mail" attribute, if my group has no it ?

This is a query to get all attributes of group:

ldapsearch -H ldap://127.0.0.1   -D
"uid=addressbook,ou=People,dc=xxx,dc=org" -b
ou=PostGroup,ou=People,dc=xxx,dc=org  '(cn=all)'    -W
Enter LDAP Password:
# extended LDIF
#
# LDAPv3
# base <ou=PostGroup,ou=People,dc=xxx,dc=org> with scope subtree
# filter: (cn=all)
# requesting: ALL
#


# all, PostGroup, People, xxx.org
dn: cn=all,ou=PostGroup,ou=People,dc=xxx,dc=org
cn: all
gidNumber: 500
memberUid: george
memberUid: testuser
objectClass: posixGroup
objectClass: top

# search result
search: 2
result: 0 Success

# numResponses: 2
# numEntries: 1


If i make this query:
ldapsearch -H ldap://127.0.0.1 -D
"uid=addressbook,ou=People,dc=xxx,dc=org" -b
ou=PostGroup,ou=People,dc=xx,dc=org '(cn=all)' memberUid gidNumber mail
-W

i get:
# extended LDIF
#
# LDAPv3
# base <ou=PostGroup,ou=People,dc=xxx,dc=org> with scope subtree
# filter: (cn=all)
# requesting: memberUid mail
#

# all, PostGroup, People, xxx.org
dn: cn=all,ou=PostGroup,ou=People,dc=xxx,dc=org
memberUid: georgiy.a.sitov
memberUid: testuser

# search result
search: 2
result: 0 Success

# numResponses: 2
# numEntries: 1

But i can not get "mail" attribute directly.

May be i can use "extract", but in "google" i can not find explain.

Please, can you help me make query
?



>
> *IF* you need more data, which is what was suggested to me by the fact
> that you were asking for memberUid, then it gets more complicated. I
> pointed to ${extract}, I should also have pointed to ${map}. It's easy
> to construct, but it's apparently not what you want.
>
> -Phil
>




--
Best regards, George.