[Exim] plain auth match using crypteq

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I'm trying like heck to get this working (I'm presenting about exim to
SeaBUG tomorrow and really need a working example).

I want to do PLAIN AUTH against a file where each line of the file has a
username:password

The password is MD5 encrypted.

So here is the authenticator
# This should allow encrypted passwords in authplain file
lookup_plain:
  driver = plaintext
  public_name = PLAIN
  server_condition = ${lookup{$2}lsearch{/usr/local/etc/exim/authplain}\
    {${if crypteq{$3}{\{md5\}$value}{yes}{no}}}{no}}
  server_set_id = $2

Here is the authplain file
mdf:45ebd07ed0eea75cfdc99df2b0887821

Relevant output from exim -bd -d...
4984 SMTP<< AUTH PLAIN AG1kZgBtaXNobWFzaA==
4984 search_open: lsearch "/usr/local/etc/exim/authplain"
4984 search_find: file="/usr/local/etc/exim/authplain"
4984 key="mdf" partial=-1 affix=NULL starflags=0
4984 LRU list:
4984 9/usr/local/etc/exim/authplain
4984 End
4984 internal_search_find: file="/usr/local/etc/exim/authplain"
4984 type=lsearch key="mdf"
4984 file lookup required for mdf
4984 in /usr/local/etc/exim/authplain
4984 lookup yielded: 45ebd07ed0eea75cfdc99df2b0887821
4984 crypteq: using MD5+hex hashing
4984 subject=156335A148E8AA271069C550CC514586
4984 crypted=45ebd07ed0eea75cfdc99df2b0887821
4984 lookup_plain authenticator:
4984 $1 =
4984 $2 = mdf
4984 $3 = mishmash
4984 expanded string: no
4984 SMTP>> 535 Incorrect authentication data


What does the subject mean in the output and why isn't it matching?
Any ideas? TIA!
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Some days it's just not worth chewing through the restraints...
Mark D. Foster, CISSP <mark@???> http://mark.foster.cc/

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