Great,
Thanks for the info, but the example I copied this from was meant
for just PLAIN. There's a login example below it too...
Anyway, thanks!
-Cameron
-------
http://21andover.com
On Fri, 21 Dec 2001, Kirill Miazine wrote:
> * Cameron <hiryu@???> [20011221 03:50]:
> > plain:
> > driver = plaintext
> > public_name = PLAIN
> > # server_condition = "${if
> > crypteq{$2}{${extract{1}{:}{${lookup{$1}lsearch{/e$
> > server_condition = "${if
> > crypteq{$3}{${extract{1}{:}{${lookup{$2}lsearch{/et$
> > # server_set_id = $1
> > server_set_id = $2
> >
> > I did the above, the old stuff is commented out, that fixed the problem...
> >
> > I'm a bit confused, it seems that the username should be in $1 and the
> > password should be in $2. This authentication setup is really just an
> > example from the "default" debian exim.conf, and I see it's made with the
> > assumptoin that $1/$2 should be the user/pass.
> >
> > I first did it by hand to make sure it works, then I tried it in
> > evolution.. still works.
> >
> > Of course, if I ever figure out what's wrong, I can fix it myself by
> > uncommenting the old lines, and commenting the new lines.
>
> When using PLAIN, username is stored in $2 and password is in $3. When
> using LOGIN, username is in $1 and password is in $2.
>
> --
> Kirill
>
