[Exim] Crazy expansion

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Συντάκτης: Dave C.
Ημερομηνία:  
Προς: exim-users
Αντικείμενο: [Exim] Crazy expansion

I need to write a condition for an authenticator, that I know is going
to be a nightmare, and I'm hoping someone that is a lot more expert
than I at crufting these things can help. I know the general concept I
need, I'm just not familiar with the exact syntax.

(I know I will get some RTFM responses. I am R'ing the FM and am just
hoping perhaps someone can help me do it a little faster)

The authenticators are currently as follows, which is fairly
straightforward.

fixed_login:
  driver = plaintext
  public_name = LOGIN
  server_prompts = "Username:: : Password::"
  server_condition = "\
      ${if pam {$1:$2}{yes}{no}}"
  server_set_id = $1


fixed_plain:
  driver = plaintext
  public_name = PLAIN
  server_condition = "\
    ${if pam {$2:$3}{yes}{no}}"
  server_set_id = $2



I need to modify these to succeed if either the pam check succeeds -OR-

1. The username-part of the auth data contains an "@"

(if $1 contains "@" then () else pam () ) ?

2. A directory exists, /path/to/<DOMAINPART>, where <DOMAINPART> is the
portion of the username-part after the "@"

3. There exists in that directory a file /path/to/<DOMAINPART>/passwd,
which contains a standard username/password pair, and the username
in the file matches the portion of the username-part of auth data
which is before the "@"

(exists : /path/to/(substr(everything_after(@)($1)))/passwd ) ?

4. The password for that username in the file matches (with crypt) the
password-part of the auth data.

(lsearch in file /path/to/(substr(everything_after(@)($1)))/passwd with a key of
(substr(everything_before(@)($1))) = crypt($2) ) ?

An example:

There is a file /path/to/some-domain.com/passwd, which contains (among
other entries):

|
|webmaster:T0dKpGFFwan8o
|


If the client provides

"webmaster@???" as a username, and "12345" (which matches
the crypt above) as a password, it should satisfy the auth criteria