On Tue, 26 Aug 2008, Hiroshi OHNO wrote:
> I attach the small program. (I use PCRE in Fedora9)
> The result of this program is different from the regular expression of Perl.
> Is the first result of this program right?
Which release of PCRE? The current release (7.7) behaves just like Perl:
$ pcretest zz
PCRE version 7.7 2008-05-07
/^(?!JP)[a-z]*$/i
jp
No match
JP
No match
cn
0: cn
CN
0: CN
> int main(int argc, char *argv[])
> {
> int i;
> for(i = 1; i < argc; i++) {
> const char *errptr;
> int erroffset;
> pcre *preg = pcre_compile("^(?!JP)[a-z]*$", PCRE_CASELESS, &errptr, &erroffset, NULL);
> if(preg == NULL) {
> if(errptr) {
> printf("Error:%s\n", errptr);
> }
> continue;
> }
>
> pcre_extra extra;
> int rc;
> if((rc = pcre_exec(preg,&extra, argv[i], strlen(argv[i]), 0, 0, NULL, 0)) >= 0) {
You are calling pcre_exec() with "extra" unset. This could cause
trouble. Try using NULL instead.
> printf("match(%d):'%s'\n", rc, argv[i]);
> } else {
> printf("unmatch(%d):'%s'\n", rc, argv[i]);
> }
> pcre_free(preg);
> }
>
> return 0;
> }
Philip
--
Philip Hazel
